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Trains A and B leave the same city at the same time, headed eat and north respectively. Train B travels 5 mi/hr faster than train A. After 2 hours they are 50 miles apart. Find the speed of each train.

Can you also show me how?

2006-12-10 15:09:36 · 2 answers · asked by Jimmy F 1 in Education & Reference Homework Help

2 answers

train a is travelling at 10 mls/hr
train b is travelling at 15 mls/hr

take away the difference between the 2 trains (5 mls by 2 hrs =10mls)you can then say that the distance covered by each train if the speed was the same would be 20 mls over 2 hrs.

2006-12-10 15:20:45 · answer #1 · answered by geoff a 1 · 0 0

One train is going 15mph, the other is 20 mph
you have to ignore that other answer because he doesnt realise that the trains are traveling at right angles, he thinks they're traveling in opposite directions.

The first thing you do is draw a triangle. one line goes up (north) and the other goes right (east). the line that connects these 2 (the one that completes the triangle) you know equals 50 miles. You will use the pythagorean theorum (c squared equals a squared plus b squared)

The problem also says that one train travels 5 miles faster than the other and the trains travel for two hours. After 2 hours, the faster train has traveled 10 more miles. (2 hours times 5 miles per hour.)

I have labeled one side of the triangle X and the other side X+10.

I am working on the rest, I will edit my answer

2006-12-10 23:44:29 · answer #2 · answered by person 3 · 0 0

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