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If the Hubble Space Telescope proved that Hubble's constant is actually half as large as it is currently believed to be, what would the implied age of the universe be in comparison to the current accepted value?

hubbles constant is 70 km/s/mpc

Four times the accepted value
One fourth of the accepted value
Half of the accepted value
The same as the accepted value
Two times the accepted value
None of the Above

2006-12-10 15:00:40 · 1 answers · asked by EarthboundB 1 in Science & Mathematics Astronomy & Space

1 answers

One Megaparsec (Mpc) is 3.085x10^19 km.

For H = 70 km/s per Mpc, objects were at distance 0 from each other at

1 Mpc/H = 3.085x10^19 km/Mpc divided by 70 km/(s*Mpc) = 4.4x10^17 seconds

If H is only 35, then the age is 8.8x10^17 seconds

2006-12-10 15:08:28 · answer #1 · answered by Raymond 7 · 1 0

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