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2006-12-10 14:42:09 · 7 answers · asked by Myda C 2 in Science & Mathematics Mathematics

7 answers

2^x = 7

x = log base 2 of 7

x = log (7) / log (2)

x = 2.807354922...

2006-12-10 14:45:40 · answer #1 · answered by Holymasteric 3 · 0 0

2*x = 7
Take natural log of each side getting:
ln2^x = ln 7
xln2 = ln 7 [ Prroperty of logarithms]
x =(ln 2)/(ln 7)
The above is an exact answer. Yiu can get an approximate answer using your calculator or using a table of natural logs.

2006-12-10 14:49:13 · answer #2 · answered by ironduke8159 7 · 0 0

To do this problem you need to know logs. No the mathematical logarithms, not dead trees.

First convert the eqn to log form:

2^x = 7 >>> log_2 (7) = x

Now just enter this into a calc (log 7)/(log 2) and you should get approx. 2.8074

2006-12-10 14:46:55 · answer #3 · answered by AibohphobiA 4 · 0 0

To find x, take the log of both sides.
log(2^x) = log 7

Then pull the x from the exponent and put it in front of the log:
xlog2 = log7

Divide by log2: x = log7/log2

Voila!

2006-12-10 14:48:43 · answer #4 · answered by Steve 7 · 0 0

2^x=7 take ln of both sides
x ln 2=ln 7 divide by ln 2
x=ln 7 / ln 2=2.807

2006-12-10 14:46:13 · answer #5 · answered by yupchagee 7 · 0 0

If you take the natural log of both sides you get:
ln(2^x)=ln7

You can then pull the x out to get:
xln(2)=ln7

So x=ln7/ln2=2.807

2006-12-10 14:47:52 · answer #6 · answered by Mike 3 · 0 0

2x2x2x2x2x2x2 =128

2006-12-10 14:50:48 · answer #7 · answered by harold g 2 · 0 0

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