2^x = 7
x = log base 2 of 7
x = log (7) / log (2)
x = 2.807354922...
2006-12-10 14:45:40
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answer #1
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answered by Holymasteric 3
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2*x = 7
Take natural log of each side getting:
ln2^x = ln 7
xln2 = ln 7 [ Prroperty of logarithms]
x =(ln 2)/(ln 7)
The above is an exact answer. Yiu can get an approximate answer using your calculator or using a table of natural logs.
2006-12-10 14:49:13
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answer #2
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answered by ironduke8159 7
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To do this problem you need to know logs. No the mathematical logarithms, not dead trees.
First convert the eqn to log form:
2^x = 7 >>> log_2 (7) = x
Now just enter this into a calc (log 7)/(log 2) and you should get approx. 2.8074
2006-12-10 14:46:55
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answer #3
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answered by AibohphobiA 4
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To find x, take the log of both sides.
log(2^x) = log 7
Then pull the x from the exponent and put it in front of the log:
xlog2 = log7
Divide by log2: x = log7/log2
Voila!
2006-12-10 14:48:43
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answer #4
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answered by Steve 7
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2^x=7 take ln of both sides
x ln 2=ln 7 divide by ln 2
x=ln 7 / ln 2=2.807
2006-12-10 14:46:13
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answer #5
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answered by yupchagee 7
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If you take the natural log of both sides you get:
ln(2^x)=ln7
You can then pull the x out to get:
xln(2)=ln7
So x=ln7/ln2=2.807
2006-12-10 14:47:52
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answer #6
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answered by Mike 3
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2x2x2x2x2x2x2 =128
2006-12-10 14:50:48
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answer #7
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answered by harold g 2
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