if x/y = x + y. what does y equal?

Question

just bear with me. Thanks. show how you solve this please

Answer 1

x/y=x+y
Multiply by y:
x=xy+y²
Add (x/2)²:
x+x²/4 = y²+xy+x²/4
Factor the right-hand side:
x+x²/4 = (y+x/2)²
Take the square root of both sides:
y+x/2 = ±√(x+x²/4)
Subtract x/2:
y=-x/2±√(x+x²/4)
And we are done.

Answer 2

(x / y) = x + y --- Multiply both sides by y to get rid of the initial fraction...
x = y² + yx --- Subtract x from both sides...
y² + xy - x = 0 --- We now have a quadratic equation in general form (ax² + bx + c = 0). We can solve for y using the quadratic formula: x = [-(b) ± √(b² - 4ac)] / 2a. For our purposes, x = y, a = 1, b = x, and c = (-x).

y = [-(x) ± √(x² - 4(1)(x))] / 2(1)
y = [-x ± √(x² - 4x)] / 2

Answer 3

x/y=x+y
Multiply by y:
x=xy+y²
Add (x/2)²:
x+x²/4 = y²+xy+x²/4
Factor the right-hand side:
x+x²/4 = (y+x/2)²
Take the square root of both sides:
y+x/2 = ±√(x+x²/4)
Subtract x/2:
y=-x/2±√(x+x²/4)

Answer 4

Okay you could try it this way.
Multiply both sides by y and you get
x = xy+y^2
then subtract xy from both sides to get
y^2 = x-xy
then take the square root of both sides to get y

Answer 5

x/y=(x+y)/1

cross multiply

x=y2+yx

y2+yx-x=0.

i think y can equal anything EXCEPT ZERO, since you can't have zero in the denominator.

Answer 6

x/y = x + y

subtract x from both sides...
x/y - x = x - x + y
x/y - x = 0 + y
x/y - x = y

Answer 7

x/y-x=y

just subtract x from both sides