A weight lifter lifts a set of weights a vertical distance of 2.00m. If a constant net force os 350N is exerted on teh weights, how much work does the weight lifter do on teh weights?
Wnet = (350N) (2.00m) (cos 90) = 0 J
Is this correct?
2006-12-10 13:00:12 · 4 answers · asked by billf39 2 in Science & Mathematics ➔ Physics
drop the cosine of 90. He's performing work in the same direction as force so just 2 times 350 equals 700 joules
2006-12-10 13:03:15 · answer #1 · answered by Anonymous · 0⤊ 0⤋
In the direction of force, it is sin 90 and sin 90= 1.
The answer is 700 J.
2006-12-10 13:15:04 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
cos is the right trig function to use. But take the cos of the angle between the direction of the force and the direction of the displacement. In this case it would be cos(0).
2006-12-10 13:21:23 · answer #3 · answered by sojsail 7 · 0⤊ 0⤋
an identical % is the answer because because it were given darker it concurrently were given cooler. warmth from the solar is provided in a sort of kinds of radiation, all vacationing on the speed of light.
2016-11-25 19:46:22 · answer #4 · answered by ? 4 · 0⤊ 0⤋