2006-12-10 12:25:18 · 17 answers · asked by Heather H 1 in Science & Mathematics ➔ Mathematics
1 + 3 + 5 + 7 + 9 + 11 + 13 = 49
2006-12-10 12:27:09 · answer #1 · answered by Xiangwei Xi 3 · 0⤊ 1⤋
1+3+5+7+9+11+13 = 49
2006-12-11 22:54:17 · answer #2 · answered by SHUBHANGI 1 · 0⤊ 0⤋
1+3+5+7+9+11+13=49 or first and last sum of positive odd number of first 7 is 7
2006-12-10 21:47:32 · answer #3 · answered by mani k 2 · 0⤊ 0⤋
1+3+5+7+9+11+13 = 49
2006-12-10 12:27:48 · answer #4 · answered by x7i8zkoreanx 2 · 0⤊ 1⤋
1 + 3 + 5 + 7 + 9 + 11 + 13 = 49.
In general, the sum of the first n positive odd numbers is n^2.
2006-12-10 12:27:30 · answer #5 · answered by Anonymous · 0⤊ 2⤋
1+3+5+7+9+11+13=49
2006-12-10 12:28:11 · answer #6 · answered by schloemdawg08 1 · 0⤊ 1⤋
Its 49
2006-12-10 20:00:26 · answer #7 · answered by babu 2 · 0⤊ 0⤋
49
2006-12-10 17:00:18 · answer #8 · answered by deepak g 1 · 0⤊ 0⤋
1 +3+5 +7 +9+11+13
= 49
simple calculation. you have wasted 5 pionts.
2006-12-10 13:47:12 · answer #9 · answered by Meera 3 · 0⤊ 0⤋
the formula for the first n odd numbrs is n^2
so the sum of the first 7 odd nos is 7^2=49
2006-12-10 13:45:12 · answer #10 · answered by raj 7 · 0⤊ 1⤋