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1. If f(x)=3cos(2ln(x)), find f'(x).

2. let f(x)=[x^2(x-5)^9]/(x^2+4)^3
Use logarithmic differentiation to determine the derivative.
f'(x)=?

3. Evaluate the indefinite integral
∫6e^(6x)sin(e^(6x))dx

2006-12-10 12:06:13 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

Ill do my very best.

1) Chain rule => 3cos([2lnx])=> -3sin(2lnx)*d/dx 2lnx => Answer=> -3sin(2lnx)* (2/x)

2) Number 2 was ridiculous so im just giving the answer.
3(x^2+4)^2 * 2x[X^2(x-5)^9] - 2x(x-5)^9 + 9(x-5)^8 *x^2 *[(x^2+4)^3] / (x^2+4)^6


3) u substitution let u= e^6x

Answer -cos(e^(6x)) + c

2006-12-10 12:37:57 · answer #1 · answered by roncho 4 · 0 0

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