English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I'm told to use double integrals to calculate the area of the region bounded by

y = 2x
x = 0
y = 1 - 2x - x²

I know how to set up and calculate the double integral, so I don't need help with that.

However, when I graph this, I see two different regions that are bounded by these lines, one region to the left of x = 0 and one to the right of x = 0. Am I seeing this correctly?

(I'm going to calculate the area for both regions, unless someone can prove to me that there is only one region with these bounds.)

2006-12-10 11:39:16 · 2 answers · asked by q_midori 4 in Science & Mathematics Mathematics

I've given all the information that I have, which is why I posted my question.

I think all I can do is calculate the areas for the two different areas. I'm just trying to see if anyone else agrees or disagrees (and why).

2006-12-10 11:47:27 · update #1

2 answers

There are two different regions, as you say. Is there something in your problem statement that would allow you to eliminate the area where x<0?

Some problems have an implicit limit on the integral because it is a physical problem. Other problems may explicitly say integrate from x=0 to x=infinity (or the other limit).

There must be a way to discriminate between the two regions; otherwise, the x=0 contraint would be irrelevant.

2006-12-10 11:54:52 · answer #1 · answered by Bears 2 · 1 0

more info plz

2006-12-10 11:41:18 · answer #2 · answered by Anonymous · 0 2

fedest.com, questions and answers