For the following unbalanced equation Cu2S + O2 > Cu2O + SO2
How many moles of the second reactant O2 would be needed per mole of the first reactant Cu2 in order to complete the reaction?
What volume of oxygen gas, measured at 27.5 degrees Celsius and 0.998 atm is needed to react with 25 grams of the first reactant Cu2S?
What volume of sulfur dioxide gas is produced under the same conditions?
2006-12-10 11:19:57 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First things first, balance the equation. There's a reason why it says it's not balanced. You can't use an unbalanced equation for stoichiometric proportions.
Balanced your equation looks like this:
2Cu2S + 5O2 -> 2Cu2O + 4SO2
For the first problem know that for every 2 mol of Cu2S, you need 5 mol of O2 to react with it.
For the second problem, use the ideal gas law pv= nrt. Convert 25 g of Cu2S to moles and find how many moles of O2 gas you need through stoichiometric proportions. Plug into the gas law and solve for volume.
For the third question repeat the following but replace O2 with SO2.
2006-12-10 11:30:22 · answer #1 · answered by hmm123 2 · 0⤊ 0⤋
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2016-12-18 11:06:55 · answer #2 · answered by ? 4 · 0⤊ 0⤋
2Cu2S + 3O2 ===> 2Cu2O + 2SO2
1molCu2S x 3molO2/2molCu2S = 1.5molO2
25gCu2S x 1molCu2S/162gCu2S x 3molO2/2molCu2S x 22,400mLO2/1molO2 x 300.5K/273K x 0.998atm/1.000atm = (25)(3)(22,400)(300.5)(0.998)/162)(2)(273) = mLO2
The SO2 is the same, except instead of 3molO2/2molCu2S, you write 2molSO2/2molCu2S = 1molSO2/1molCu2S
Notice how all the units of the given cancel until you get units of the answer.
2006-12-10 11:50:51 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋
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2006-12-10 11:23:18 · answer #4 · answered by booyah™ 7 · 0⤊ 0⤋