one-to-one function with inverse? how to do?

Question

f(x) = 2x^2 - 36
If the following defines a one-to-one function, find the inverse.
Help please! How do you solve this?

Answer 1

y = 2x^2 - 36
y + 36 = 2x^2
sqrt( y/2 + 18) = x

f(y) = sqrt(y/2 + 18)

basically, the question is: if your function was that when you input x you get y, find one that when you input y, you'll get x

Answer 2

To get inverse of a function first rewrite your equation so it looks like this: y = 2x^2 -36.
Now, switch the x and y so it looks like this : x = 2y^2 -36.
Solve for y in this equation. This is the function for the inverse.
You should get this: y = sqrt[(x+36)/2]

Answer 3

Swap the X and Y spaces then solve for Y.

So you get
X = 2y^2-36

Now you want Y by itself on one side so:
2y^2 = X + 36
y^2 = x/2 + 18
y = squareroot(x/2 + 18)

Answer 4

y=2x^2-36
+36 +36

y+36=2x^2
------- ------
2 2

y/2+18=x^2

x= the square root of y/2+18

Answer 5

F(X)=2X^2 - 36

F(X)/2=X^2-18
F(X)/2+18=x^2
sqrt(F(X)/2+18)=X

Answer 6

2y^2-36

Answer 7

instead of saying f(x) just put y
so y=2x^2-36
inverse; x=2y^2-36
u might have to get y by itself tho