Cool math problem... can you help?

Question

Lemonade Fun

Anne and Joe decide to sell lemonade on a hot summer day. They’re selling two sizes a 25-cent cup and a smaller 10-cent cup. At the end of the day, they’ve made $8.45.

They count the number of empty cups remaining. They started out with equal numbers of large and small cups, but now have three more small cups than large. How many cups of each size lemonade did they sell.

I NEED THREE DIFFERENT EQUATIONS/WAYS TO DO THIS... I know guess and check. other info: I have a T183 graphing calc.

HOW DO YOU GRAPH IT.... Would you intersect? (i know how to do that)

Answer 1

One way is substitution.
You set up the 2 equations:
0.25x + 0.10y = 8.45
x = y + 3
In this case X= large cups, y = small

Then you substitute the x in the first equation with (y+3) and get:
0.25(y+3) +0.10y = 8.45

The answer you get is that y=22, which means x = 25

You could also do it on your calculator, but I don't have the same one as you, so I can't help you there.
Oh, and you can solve it as a matrix...

Answer 2

Because they have 3 more small cup than large cups, they sold 3 more large cups than small cups. Let S equal the number of small cups sold. The number of large cups sold is then S+3.
S x $0.10 + (S+3) x $0.25 = $8.45. I'll let you do the math. I do not see 3 independent equations in this problem. I could write one equation with 2 unknowns (S x $0.10 + L x $0.25) = $8.45) which would give the total income, and another equation which give the relationship between the number of large cups sold and the number of small cups sold (S = L+3).
. Because I am so old that I never used a graphing calculator in school I cannot graph this problem. However, I have no problem solving them. The graphing calculator is over-used.

Answer 3

let x be the number of large cups sold
then x-3 is the number of small cups sold

so .25x + .10(x-3) = 8.45

You should be able to solve it from there. It's just one equation. Your answer will give you the number of large cups sold, then you can subtract 3 from that to get the number of small cups sold.


Another way - let x = the number of small cups sold
then x+3 is the number of large cups sold

set up the equation the same way as in the earlier example, and solve for the number of small cups, then add 3 to get the number of large cups sold

Answer 4

Make S1 = # of small cups at the start of the day, L1 = # of large cups at the start of the day and S2 and L2 equal to the small and large cups at the end of the day.

Now, write down all the equations you can relating those variables. Then solve those equations.



Here are the equations that you need to solve (try and find them yourself first.)

S1=L1
they have an equal number of cups at the beginning of the day.

25(L1-L2)+10(S1-S2)=845
they made 845 cents by selling large cups for 25 cents and small cups for 10 cents.

S2=L2+3

Answer 5

Only two equations with 2 unknowns. Let x = number of large cups sold and y = number of small cups sold.

Then .25x + .10y = 8.45 and

x + 3 = y

Solve for x and y.

Answer 6

there are 4 cups left

Answer 7

first fill the 5ounce bottle and from it fill the 3ounce bottle. Then empty the 3ounce bottle fill it with the remaining of the 5ounce bottle, it means that now you have 2ounce in 3ounce bottle. So fully fill the 5ounce bottle again & then fill the partially filled 3ounce bottle. And in the 5ounce bottle you will find 4ounces.

Answer 8

I know this aint an answer.. But answer some more of mine dude.. You get 2 points for answering and I'll give you best answer for one of the questions. 'coz one of them I may give best answer on that one you answered.. Cool thanks..

Answer 9

Go to:

www.cheatonyourhomeworkandyoullgetanf.com

Answer 10

No and math is not cool get a life