algebraic problem?

Question

i really dont remember how to do this problem..........

the tickets for a dance recital cost $5.00 for adults and $2.00 for children. if the total number of tickets sold was 295 and the total amout collected was $1220, how many adult tickets were sold?(only an algebraic solution can receive full credit.)................please help meee!!!!!

Answer 1

Let x=amount of adult tickets sold
Let y=amount of children tickets sold
Then,
1) x+y=295
2) 5x+2y=1220
Solve the system.
1) y=295-x
Substitute 1 into 2
5x+2(295-x)=1220
5x+590-2x=1220
3x=630
x=210
Substitue x into 1
y=295-210
y=85
Therefore, there were 210 adult tickets sold and 85 children tickes sold.

Answer 2

Set up linear equations! Use x for adult tickets, and y for childrens tickets. You know x + y = 295, because that many tickets were sold in all. YOu also know 5x+2y = 1220, because of the profit. Now, solve by any method. I prefer elimination. I multiply every term in my first equation by -2, and get -2x - 2y = -590. Combined with the other equation, it simplifies to 3x = 630. Divide both sides by 3, and x = 210. Fill in for that in x+y = 295, and get 210 + y = 295. Subtract 210 from both sides, and discover that only 85 kids went, as y! Now, check your answer. 210(5) + 2(85) =?=1220, 1050 + 170 =?= 1220, 1220 = 1220! Your answer is (210, 85) :)

Answer 3

The biggest problem is always what to call your variables so that you can easilly write them down but still remember what they mean.

Let F= number of full priced tickets sold
let R= number of reduced price tickets sold

then 2R is the number of dollars received from the sale of reduced price tickets, 5F is total dollars from full-price ticket sales and
2R+5F=1220 , you can't simplify sensibly so leave it there.

let T = total number of tickets sold. You have T=R+F.

but F = (1220-2R)/5 = 244-R*2/5 so T=R(1-2/5)+244 = 295 and 3/5*R =51 so R=85 now you can substitute that back into R+F=295 to get F=210.

Answer 4

A = number of adult tickets
C = number of child tickets

A+C=295 (number of tickets sold)
C=295-A


5A+2C=1220 (cost of tickets sold)


substiting 295-A for C we get
5A+2(295-A)=1220
3A+590=1220
3A=630
A=210

Answer 5

a= the number of adult tickets sold
295-a = the number of children's tickets sold

5a + 2 (295-a) = 1220

Answer 6

like the previous musician reported while requested "how do you get to Carnegie hall: "prepare, guy, prepare." As you're attempting to study algebra, do not attempt to apply shortcuts, different than those you're taught. otherwise, you will attempt to apply them the place they don't paintings, and you will the two grow to be puzzled or get the incorrect answer. The greater algebra you do, the greater effective you will get. there is quite no incorrect way.