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The prince starts his treacherous journey long before dawn of the next day. He travels from the southeatren most porint of his castle (that is at (-11,-13) ) along the road x - 2y = 15 until it intersects with the road x = -7. here he bargins with an ancient wrrior for the purchase of his magic award. Once obtaining the sworad he travels anlong the road x = -7 untill it intersects with the raod 5y = -2x - 49.

2006-12-10 10:16:59 · 6 answers · asked by Tony Fiorilli 1 in Science & Mathematics Mathematics

The prince starts his treacherous journey long before dawn of the next day. He travels from the southeatren most porint of his castle (that is at (-11,-13) ) along the road x - 2y = 15 until it intersects with the road x = -7. here he bargins with an ancient wrrior for the purchase of his magic award. Once obtaining the sworad he travels anlong the road x = -7 untill it intersects with the raod 5y = -2x - 49.

i am supposed to draw these "roads" and plot the "intersections"

2006-12-10 10:23:32 · update #1

after that he turns and travels along the road 5y = -2x - 49 until it intersects with the road y = -5x - 19

2006-12-10 10:29:53 · update #2

6 answers

Start: (-11, -13)
1st stop (-7, -4)
Last stop (-7, -7)

You can draw the lines, right?

For the last point: Substitute [ -5x - 19] for y in 5y = -2x - 49 & solve for x & y:
5(-5x - 19) = -2x - 49
Last point is (-2, -9).

2006-12-10 10:26:05 · answer #1 · answered by S. B. 6 · 0 0

So? Graph the 3 equations on some graph paper. You are either looking where he winds up, which should be easy to solve for, or you're looking for the distance traveled, for which you need to use the Pythagorean theorem to find.

2006-12-10 18:22:29 · answer #2 · answered by arbiter007 6 · 0 0

What's the question?

2006-12-10 18:19:03 · answer #3 · answered by grigri9 2 · 0 0

It certainly is a "word problem."
No question about that - unfortunately, there's no question, period.

2006-12-10 18:21:16 · answer #4 · answered by LeAnne 7 · 0 0

So...what's the question?

2006-12-10 18:19:26 · answer #5 · answered by anonymousperson 4 · 0 0

wat r u asking?

2006-12-10 18:20:25 · answer #6 · answered by Lacey 3 · 0 0

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