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3 answers

You really ought to use parentheses, even if you don't put your question in equation form. Your function could be interpreted as
1) 4*sqrt(x^3)+2 or
2) 4*sqrt(x)^3+2 or
3) (4*sqrt(x))^3+2,
and the 3rd option is not the same as the other two.
Assuming either 1 or 2, we have 4*x^(3/2)+2. The derivative is
(3/2)*4*x^(3/2 - 1), or 6*x^(1/2).
Assuming option 3 we have (4*x^(1/2))^3+2, or 4^3*x^(3/2)+2. The derivative for this is (3/2)*4^3*x^(3/2 - 1), or 96*x^(1/2).

2006-12-10 09:16:11 · answer #1 · answered by kirchwey 7 · 0 0

you really ought to use parentheses, even if you don't put your question in equation form. Your function could be interpreted as
1) 4*sqrt(x^3)+2 or
2) 4*sqrt(x)^3+2 or
3) (4*sqrt(x))^3+2,
and the 3rd option is not the same as the other two.
Assuming either 1 or 2, we have 4*x^(3/2)+2. The derivative is
(3/2)*4*x^(3/2 - 1), or 6*x^(1/2).
Assuming option 3 we have (4*x^(1/2))^3+2, or 4^3*x^(3/2)+2. The derivative for this is (3/2)*4^3*x^(3/2 - 1), or 96*x^(1/2).

2006-12-10 17:45:12 · answer #2 · answered by unnamed 1 · 0 2

I am assuming you mean 4* x^2/3 + 2 ?

Deriv = 2/3 * 4 x^(2/3-1) + 0

= 2/3*4 X^-1/3

=8/3 * x^-1/3

2006-12-10 16:51:59 · answer #3 · answered by bkc99xx 6 · 0 0

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