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how do you solve this as a math problem? the question is how do you solve 3! show work

2006-12-10 07:57:42 · 10 answers · asked by metzfan753 1 in Science & Mathematics Mathematics

10 answers

3! is read as "3 factorial".

One definition of the factorial of a integer is, the product of the integer itself, and all the integers less than it. (And 0! is just defined to be 1.)

So 3! = 3 x 2 x 1 = 6

2006-12-10 08:04:55 · answer #1 · answered by Jim Burnell 6 · 0 0

3 X 2 X 1 = 6 I believe

2006-12-10 08:04:19 · answer #2 · answered by Anonymous · 0 0

1*2*3=6

2006-12-10 08:03:34 · answer #3 · answered by pneumaticpanther 1 · 0 1

For any number, the ! sign denotes the "factorial" function. The factorial function is actually pretty simple, though the numbers grow very quickly.

To compute a factorial, you multiply every number from 1 to the specified number. So, for example:
3! = 1 * 2 * 3 = 6,
4! = 1 * 2 * 3 * 4 = 24,
5! = 1 * 2 * 3 * 4 * 5 = 120,
7! = 1 * 2 * 3 * 4 * 5 * 6 * 7 = 5040,
and so on.

2006-12-10 08:06:00 · answer #4 · answered by happymutant42 1 · 0 0

Actually it's times

1 x 2 x 3 = 6

(but it's still 6)

2006-12-10 08:06:54 · answer #5 · answered by thkiabdks 2 · 0 0

factorial formula is
n! = (n) (n-1) (n-2) (n-3) ....
3! = (3)(2)(1)
3! = 6

2006-12-10 08:09:05 · answer #6 · answered by racz_jay25 2 · 0 0

3! is read as three factorial and is equal to

3*2*1

Similarly, 5! = 5*4*3*2*1

2006-12-10 08:05:08 · answer #7 · answered by Anonymous · 0 0

multiply 3x and x together which makes 4x squared then multiply 3x and y= 3xy 3xsquared + 3xy - 2x + 2y - 3y + 12x

2016-05-23 02:41:20 · answer #8 · answered by Rebecca 4 · 0 0

1!=1
2!=2x1=2
3!=3x2x1=6
4!=4x3x2x1=24
...etc.

2006-12-10 08:05:09 · answer #9 · answered by faxdude 1 · 0 0

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