need help in makeing a graph.?

Question

Given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation, give one additional point on this line and graph the function.

Equation of line in slope-intercept form
Give one additional point in (x,y) form that would fall on this line:

Graph the function:

Answer 1

First pick two points and calculate the slope.

I picked (1,3) and (2,4)

m = (y2 - y1)/(x2 - x1)
m = (4 - 3)/(2 - 1) = 1 /1 = 1

So we know the slope-intercept form will look like:

y = (1)x + b = x + b

Just pick a point, plug in its x and y values, and solve for b:

I picked (1,3)

3 = 1 + b
b = 2

So the slope-intercept form of the equation is:

y = x + 2

I hope you know how to graph using the slope-intercept form. In this case, you would start on the y-axis, go up 2, and put a dot. That's the y-intercept.

Then, since the slope is the "rise over the run", and the slope is 1 = 1/1, you go up one square and to the right one square and put another dot. That's your second point. Draw a line through those two points.

And then it should be easy to pick out other points. (0,2) for example.

Answer 2

So, what's the problem?

Start with the point-slope form and convert to slope intercept.