2 NH4NO3(s) 2 N2(g) + 4H2O(g) + O2(g)
What is the total number of liters of gas formed when 233 g NH4NO3 is decomposed?
the answer is expressed in L
2006-12-10 07:29:18 · 3 answers · asked by Jackson G 1 in Science & Mathematics ➔ Chemistry
Balance the equation, determine how many mols of Ammonium Nitrate based on its weight, divide the second result by the first, multiply the right side the equation by this result to determine the mols of each gas produced. Use your ideal gas laws and such to take a stab at the resulting volume.
2006-12-10 07:34:31 · answer #1 · answered by DJL2 3 · 0⤊ 0⤋
The trick in this question is to add up all the moles of gas together: 2 + 4 + 1 = 7.
So you have a 2:7 mole ratio.
Now work out the moles of ammonium nitrate (233/80) and multiply it by 7/2.
Your question does not state the conditions under which the volume of the gases is to be measured, but I would assume it is RTP. In that case, multiply the total number of moles of gas by 24 for your final answer.
2006-12-10 07:34:37 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
The book says 228g NH4NO3. Just sayin .
2016-05-23 02:39:20 · answer #3 · answered by Rebecca 4 · 0⤊ 0⤋