If 3.23 g of methane gas (CH4) is introduced into an evacuated 3.56 L container at 32°C,?

Question

what is the pressure in the container?

the answer is expressed in kPa

Answer 1

Use the Ideal Gas Law: PV = nRT

P = pressure (this is your unknown; it will be in kPa if you use the correct value for R)
V = 3.56 Liters (gases expand to fill the available space)
n = moles of gas (change your grams to moles by dividing by the molecular mass of methane, CH4)
R = gas constant (8.2 since you want pressure in kPa)
T = Kelvin temperature (C = 273).

Plug the numbers in and solve for pressure.