A sealed cylinder of gas contains nitrogen gas at 1.00 103 kPa pressure and a temperature of 27°C.?

Question

The cylinder is left in the sun, and the temperature of the gas increases to 56°C. What is the new pressure in the cylinder?

the answer is expressed in kPa

Answer 1

OK.

This is an applied ideal gas law problem, where volume and molar amount of gas is kept constant, but pressure and temperature vary.

PV=nRT Since V, n, R are constant, P= KT or P/T=K
{This is sometimes called Gay-Lussac's Law.}

Remember that temperature must be in degrees above absolute zero; for Celsius scale those degrees are in Kelvin, and are equal to 273.15 + C.
So:
27 C = 300.15 K
56 C = 329.15 K

Thus:

P/T= 103 kPa/300.15 = P/329.15

Solve for P = 112.9 kPa

Answer 2

Why would you fill a balloon with nitrogen gas?

Answer 3

PV=nRT

At the initial state, P1V=nRT1
At final state, P2V=nRT2

rearrange the equations and set it equal to each other, you will get P2=(P1/T1)*T2