Nal + Br 2 = NaBr + I 2
2006-12-10 07:15:12 · 3 answers · asked by mortifiedpengn 3 in Science & Mathematics ➔ Chemistry
Bromine in elemental form is reduced to the -1 state while iodine is oxidized from the -1 state to the elemental form. Equation need to be balanced.
2 NaI + Br2 = 2 NaBr + I2
2006-12-10 07:25:14 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
In solution, a less active element is replaced in its compounds by a more active element. As far as the halogens are concerned, the order of activity is F>Cl>Br>I. so a solution of Br2 in water will replace the I in NaI to give NaBr and I2 dissolved in water. For the chemicals in their elemental state, the same thing would probably happen if you should pour liquid bromine onto sodium iodide.
2006-12-10 15:43:48 · answer #2 · answered by kentucky 6 · 0⤊ 0⤋
What kind of explanation do you need? The question means a mixture of sodium iodide and bromine gives sodium bromide and Iodine.
2006-12-10 15:24:23 · answer #3 · answered by whatsnicknamemean 2 · 0⤊ 0⤋