Square root of 3x + 4 = x
2006-12-10 07:07:38 · 6 answers · asked by crazylifer 3 in Science & Mathematics ➔ Mathematics
square both sides:
3x + 4 = x^2
now it is a normal trinomial
x^2 - 3x - 4 = 0
(x-4)(x+1) = 0
x = 4 or x = -1
2006-12-10 07:10:56 · answer #1 · answered by alia_vahed 3 · 0⤊ 0⤋
Square root of 3X + 4 = X
(square both sides...)
(square of a square root is the expression itself)
3X + 4 = X^2
(transpose 3X + 4 to the other side of the equals sign)
X^2 - 3X -4 = 0
(X - 4)(X + 1) = 0
Now, you have two answers...
X - 4 = 0.......... and X = 4
X + 1 = 0......... and X = -1
Regards,
Zah
2006-12-10 15:18:12 · answer #2 · answered by zahbudar 6 · 0⤊ 0⤋
rewrite the equation like that
3x+4=x^2
x^2-3x-4=0
solve it and you may get this equation set
(x-4)(x+1) =0
x =4
x=-1
2006-12-10 15:14:11 · answer #3 · answered by legolian2002 1 · 0⤊ 0⤋
There is no square root of that equation.
2006-12-10 15:10:50 · answer #4 · answered by Anonymous · 0⤊ 1⤋
sqr(3x+4)=x
3x+4= x^2
x^2-3x-4
(x-4)(x+1)
x= 4 and -1
2006-12-10 15:10:08 · answer #5 · answered by 7 · 0⤊ 0⤋
use algebra. or much better idea...
google it or more simple try using a calculator
2006-12-10 15:11:03 · answer #6 · answered by EVA 2 · 0⤊ 1⤋