2006-12-10 07:01:12 · 5 answers · asked by Katy J 1 in Science & Mathematics ➔ Mathematics
log x^7 - log y
= log (x^7/y)
2006-12-10 07:03:14 · answer #1 · answered by alia_vahed 3 · 0⤊ 0⤋
Your first step is to realize that
log [base b] (a^c) = c * log [base b] (a)
Translation: Whenever you have a power within a log, you can take that power out and tack it onto the back of the log as a multiplier.
log(x^7) - log(y)
Now, remember this log property:
log [base b](a/c) = log[base b](a) - log[base b](c)
That's what we do for the above case. It now becomes a single log.
log[(x^7)/(y)]
2006-12-10 15:04:31 · answer #2 · answered by Puggy 7 · 1⤊ 0⤋
If you don't know how to do a simple math problem like this, how are you going to pass your final or understand the basics of the next math level.
Math is very cumulative. You won't be able to advance unless you truly understand the basics.
I agree with the first answer.
2006-12-10 15:19:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Do you actually do any of your homework yourself? You must really be as thick as two short planks.
2006-12-11 05:28:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋
so its x raised to the 7th over y.
2006-12-10 15:03:44 · answer #5 · answered by Juniper S 1 · 0⤊ 0⤋