5 times an interger is 36 less than the square of the interger?

Answer 1

9: 45+36=81

Answer 2

i think thats a problem in quadratic equation

let x = integer
5x = x^2 - 36 (you can equate everything to 0 by transposing)
0 = x^2 -5x - 36

solve them by quadratic expression using the factoring method
0 = x^2 -5x - 36 or x^2 -5x - 36 = 0
( x - 9 ) ( x+ 4) = 0

( x - 9 )=0 ; ( x+ 4) = 0 (equating each to 0 )

x = 9 and x = -4..

by checking using 9, we have
x^2 -5x - 36 = 0
9^2 - 5 (9) - 36 = 0
81 - 45 - 36 = 0
0 = 0

x^2 -5x - 36 = 0
-4^2 - 5 (-4) - 36 = 0
16 + 20 - 36 = 0
0 = 0

(Note: in quadratic equation, there are always two answers that's why, i am very sure of this)

Answer 3

5x = x^2-36
x^2-5x-36=0
(x-9)(x+4)=0
x = 9 is the integer solution
other solution is x = -4

Answer 4

5x = x^2 - 36
x^2 - 5x - 36 = 0
(x - 9)(x + 4) = 0
x = -4, 9

Answer 5

5x = x^2-36
x^2-5x-36=0
(x-9)(x+4)=0
x = {9, -4}