What is the slope of the lines passing through (-13,18) (27,-31)
2006-12-10 06:20:33 · 8 answers · asked by Ken H 1 in Science & Mathematics ➔ Mathematics
Slope is rise (y) divided by run (x), so in this case it would be (-31-18)/(27--13), so -49/40.
2006-12-10 06:25:48 · answer #1 · answered by Peeps 3 · 0⤊ 0⤋
The slope is equal to the rise (amout going up in the y direction) divided by the run (amount going across the x dirction)
the points given are (x1,y1) and (x2,y2)
In this case (-13,18) and (27,-31)
The slope is equal to y1-y2/x1-x2
which equals
18 - (-31) / (-13) - 27 = 49 / (-40)
or - 49/40
2006-12-10 14:25:37 · answer #2 · answered by dmxn2k 2 · 0⤊ 0⤋
m= -31-18 / 27-(-13)
m= -49/40
2006-12-10 14:22:58 · answer #3 · answered by 7 · 0⤊ 0⤋
m = (-13-27) / (18-(-31))
m = (-40) / (18+31)
m = -40/49
₢
2006-12-10 14:43:01 · answer #4 · answered by Luiz S 7 · 0⤊ 0⤋
13/14
2006-12-10 14:23:16 · answer #5 · answered by ~ME~ 3 · 0⤊ 0⤋
negative 49/40
2006-12-10 14:24:07 · answer #6 · answered by Anonymous · 0⤊ 0⤋
you can use the slope formula: m=y2(second coordinate)-y1(1st coordinate)/x2-x1
This becomes: m=18-(-31)/-13-27
m=49/-40
m=-40/49
2006-12-10 14:27:40 · answer #7 · answered by abcd 2 · 0⤊ 0⤋
i think -1.375
2006-12-10 14:24:10 · answer #8 · answered by Jono 2 · 0⤊ 0⤋