what is the maximum amount of SO3 that could be produced from 1.90 moles of O and excess S?

Question

2S+3O2-->2SO3

Answer 1

2S + 3O2 --> 2SO3

you see from the equation that to 2 moles SO3corresponds to
6 moles of O.Tcorrespond to

So 1.9 mole of O correspond to 1.9*2/3 = 1.26 mole de SO3

Answer 2

look at the balanced equation. It tells you the ratio of moles of SO3 to moles of O2 (the coefficients). Multiply by that ratio

1.90 molex O2 x 2/3 = 1.27

Answer 3

1.9 moles of O2 ?? lol ...

1.9 moles of O2 x 2/3 = 1.267 moles of SO3