58=(1+m)100
2006-12-10 05:24:16 · 12 answers · asked by gypsygirl247 3 in Science & Mathematics ➔ Mathematics
58/100 = 1 + m
.58 - 1 = m
m = -.42
2006-12-10 05:26:09 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Since 58= (1+m) times 100
(1+m) must equal the factor "58%"
so we have 58=(1+m)100
divide both sides by 100:
58/100 = 1+m
or
0.58 = 1 + m
subtract 1 from both sides:
-0.42 = m
2006-12-10 05:30:34 · answer #2 · answered by Anonymous · 1⤊ 0⤋
58=(1+m)100
58/100=1+m
m= -21/50
2006-12-10 05:28:04 · answer #3 · answered by 7 · 1⤊ 0⤋
100 + 100m - 100 = 58 - 100
The answer is -0.42
2006-12-10 05:35:10 · answer #4 · answered by TJ D 1 · 1⤊ 0⤋
58/100 = 1+m
0.58 = 1+m
0.58-1 = m
-0.42 = m
2006-12-10 05:27:13 · answer #5 · answered by love_happyfeet 1 · 1⤊ 0⤋
58=100+100m
adding -100
100m=-42
x=-21/50
2006-12-10 05:30:48 · answer #6 · answered by raj 7 · 1⤊ 0⤋
simple :
58=(1+m)100
58/100=.58
.58=(1+m)
.58-1=m
m=-.42
... therefore, m is equal to negative.42
:)
2006-12-10 05:32:57 · answer #7 · answered by Dj Unreal 1 · 1⤊ 0⤋
58=(1+m)100 (divide both sides by 100)
0.58=1+m (add -1 to both sides to leave m alone)
0.58-1=m
therefore
m=0.48
2006-12-10 05:32:20 · answer #8 · answered by nychng 2 · 1⤊ 0⤋
Easy. M=-.42
2006-12-10 05:27:06 · answer #9 · answered by Anonymous · 1⤊ 0⤋
58=100+100m
-42=100m
-0.42=m
2006-12-10 05:26:50 · answer #10 · answered by Uncle Pennybags 7 · 1⤊ 0⤋