Math question?

Question

Write an equation in slope intercept form parallel to the line y=-2x+6 and passing through the point (-2,1). and can you plz explain how to solve this type of problem

Answer 1

Slope-intercept form is

y=mx+b

so your equation is already in that form

so for the y-intercept you have
(0,?) because the first number is always zero
Then the second number is 6 because y is equal to b.

then for the x-intercept you have
(?,0) because the second number is always zero
To get the first number you plug in zero for y
so 0=-2x+ 6
and solve for x
the answer is x=3 so that is your second number
then graph your two points and draw a slop through it

hope i helped!!

Answer 2

Something I want you to keep in mind is relating words to "parallel" and "perpendicular" when it comes to lines.

Parallel - "Same slope"
Perpendicular - "Negative reciprocal"

Since we want the equation of a line parallel to the line y = -2x+6, notice that the equation of that line is y = mx + b, where m is the slope. Therefore, m = -2.

This means our new line will have that same slope m = -2.

Remember that the formula for slope is
m = (y2 - y1) / (x2 - x1)

What we do at this point is plug in the values for this slope formula as if we were calculating the slope from (-2,1), which is our given point, to (x,y), which is our general point.
Therefore, x1 = -2, x2 = x, y1 = 1, y2 = y, and m = -2.

Therefore,

-2 = (y - 1)/(x - (-2))
-2 = (y - 1)/(x + 2)
-2(x+2) = y - 1
-2x + 2 = y - 1
-2x + 3 = y

Therefore, y = -2x + 3 is the equation of our line.

Answer 3

Parallel lines always have the same slope.
The line y = -2x + 6 has a slope of -2.
So the equation you seek will look a little like:
y = -2x +b.
So what is b, you ask?
Since the line whose equation we seek passes through the point (-2, 1), then x=-2 and y=1 is a solution to the equation.
Thus the following must hold:
1 = (-2)(-2) + b.
The algebra is simple from here:
1 = 4 + b,
b = -3.
Hence, the equation you seek is:
y = -2x - 3.

Feel free to email me for clarifications.

Answer 4

Ok, if you have a line parrallel to another line, they have the same slope. So, you need to use the slope from y = -2x+6 (slope is negative 2) and the new point (-2,1). Put this into point-slope form of a line; i.e.:

y-y1 = m(x-x1) where m=slope, and (x1,y1) is the point you have to use.

Answer 5

The slope is the same, -2

The point where the straight line intercepts the y axis is a

y = - 2x + a

This line passt through the point (-2,-1)

-1 = -2*(-2) + a

And then you calculate a, you plug it into the equation.

Ana