how do you get the square root of this problem when x has an exponent of 2/81 power?

Question

sqrt(75x^2/81)

Answer 1

Divide the exponent by 2

sqrt [75 * x^(2/81)] = sqrt 75 * sqrt [x^(2/81)]

sqrt 75 = sqrt 3 sqrt 25 = 5 sqrt 3

And (2/81)/2 = 1/81

DONT FORGET TO USE ABS (x)

The result is then: 5sqrt l 3x^(1/81) l

l x l is absolute value from x

Ana

Edit: the second answer is wrong, Im sorry...

Answer 2

The square root of x^2 is x^1,
so the square root of x^(2/81) would be x^(1/81).

75 = 25 * 3 and sqrt(25) = 5,
so sqrt(75) = 5 * sqrt(3).

The final answer is the product:
5 * sqrt(3) * x^(1/81).

Answer 3

thanks Ana for pointing out the typo.i have deleted the answer