the balloon in the flask experiment?
(If not, it's where you put water into a flask and heat it to a boil, then take the flask off the flame and put a balloon over the flask's opening) What happens is that the balloon goes to the bottom of the flask, but can anyone explain exactly what happens? Does it have anything to do with any of the gas laws? (Charle's, Boyle's, Gay's)
2006-12-10 04:42:02 · 3 answers · asked by untilyoucamealong04 3 in Science & Mathematics ➔ Chemistry
A little water in the flask is heated. As the water turns to vapor it heats the air. Heated fluids (gases here) rise leaving more water vapor in the flask and less air.
You put the balloon over the flask.
You now cool the flask and the balloon gets sucked down into the flask because the water vapor turns back to liquid, taking up much less space. Air from the outside of the flask tries to rush into the flask but the balloon was in its way. That is why it was pushed down.
Heat the flask back up again and the balloon will pop back out.
Yes, of course it has something to do with the gas laws (V, T, and P).
Get an "A".
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2016-09-03 08:59:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i think the ballonn blows up
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2006-12-10 04:45:02 · answer #3 · answered by clumsy 4 · 0⤊ 0⤋