Help me in this math question ?

Question

2^x=8192
find x

show me the working

i know the answer , show me how
to get it with working

the log method is helpful , but its not what i wanted
thanks anyways

Answer 1

2^x=8192
log both sides
log 2^x=log 8192
then bring the x to the front b/c its an exponent in a log
x log 2 = log 8192
then divide log 8192 by log 2
final answer is 13

Answer 2

you could simply divide 8196 by 2 repeatedly and count how many times you do this to get to 1. (13)

or if you have a calculator or slide rule you could take the log of each side knowing that ln(2^x) = x ln(2) so x = ln(8192)/ln(2) = 13

Answer 3

Definition of logarithm: a^v = u iff v = log (base a) u.
2^x = 8192
x = log(base 2) 8192

Answer 4

No point telling him the answer...teach him how to do it...
find out how many times 8192 can be divided by 2. The digit u get is the answer

Answer 5

2^x = 8192 = 2*2*2*2*2*2*2*2*2*2*2*2*2 = 2^13
Hence, x = 13

Answer 6

The answer is 13.

Answer 7

x = 13
2^13 = 8192
Honestly, I don't know how to do it, but I did guess and check
Sorry, that I don't have the work !

Answer 8

i don't understand why people ask such questions. if you're learning it in school you schould know what steps to make to get the answer. just do it like you were taught and you should get the answer. do your own homework.

Answer 9

2^x=8912

First get the same base which is 2
so.....................

2^x=2^13

x=13

Answer 10

so 2^x=8192