Please Help:
What volume of 0.27 M sodium hydroxide is needed to react with 29.5 ml of 0.55 M phosphoric acid?
2006-12-10 03:17:00 · 3 answers · asked by slickestboy2 1 in Science & Mathematics ➔ Chemistry
Phosphoric acid is triprotic, so it will take 3 times the number of moles of sodium hydroxide to react with it.
3 * M(acid) * V(acid) = M(base) * V(base)
V(base) = 3 * M(acid) * V(acid) / M (base)
V(base) = 3 * 0.55 * 29.5 / 0.27 = 180.3 mL
2006-12-10 03:21:55 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
(M*V)for sodium hydroxide=(M*V) for phosphoric acid
if u need to drive this law tell me
so
(.27* v)=(29.5*.55)
so volumer required=60 ml
2006-12-10 11:24:10 · answer #2 · answered by ch_yaso 2 · 0⤊ 1⤋
To answer your question I would need to first balance your equation
NaOH + (phosphoric acid) = sodium phosphate + water
2006-12-10 11:21:07 · answer #3 · answered by rscanner 6 · 0⤊ 1⤋