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organic chemistry question

2006-12-10 03:06:25 · 2 answers · asked by Lisa S 1 in Science & Mathematics Chemistry

2 answers

It's hard to draw structures here, but I'll try naming a few. First thing you have to remember is that it's got two degrees of unsaturation, which could be rings or pi-bonds.

As a straight chain, it could be 1-pentyne, 2-pentyne, 1,2-pentadiene, 1,3-pentadiene, 1,4-pentadiene, or 2,3-pentadiene.

As a branched chain, it could be 3-methyl-1-butyne or 2-methyl-1,3-butadiene.

As a ring, it could be cyclopentene. Smaller rings are really too unstable, especially with a double-bond.

2006-12-10 03:14:58 · answer #1 · answered by Amy F 5 · 0 0

here are a few

structure 1
Arrange 5 carbons in a pentagon. Make a C=C bond between 2 carbons and place one H on each of those carbons. Add 2 H's to each of the 3 remaining carbons.

put H's attached to carbons on formulas below making sure there are 4 bonds to each carbon and H only forms one single bond.

structure 2
H₂C=CH-CH=CH-CH₃

structure 3
H₂C=CH-CH₂-CH=CH₂

structure 4
HC≡C-CH₂-CH₂-CH₃

structure 5
H₃C-C≡C-CH₂-CH₃

and any other isomers of above

2006-12-10 04:09:48 · answer #2 · answered by rm 3 · 0 0

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