English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

a. [(ln x)(cos x) - (1/x)(sin x)]/(ln x)^2
b. [(ln x)(sin x) + (1/x)(cos x)]/(cos x)^2
c. - [(ln x)(sin x) + (1/x)(cos x)]/(ln x)^2
d. [(1/x)(sin x) - (ln x)(cos x)]/(sin x)^2
e. none of these

2006-12-10 02:36:17 · 2 answers · asked by Doug 2 in Science & Mathematics Mathematics

2 answers

say lnx = f(x) and cosx = g(x)

[ f'(x)g(x) - g'(x)f(x) ] / g(x)^2

f'(x) = 1/x g'(x) = -sinx

answer:
(1/x)cosx + lnxsinx / (cosx)^2

choice b.

2006-12-10 02:48:11 · answer #1 · answered by Modus Operandi 6 · 0 0

that is getting ridiculous. you do not look attempting and in simple terms spouting off the solutions. The least you're able to do is try the topic after which submit what you do not comprehend approximately it.

2016-12-13 06:10:48 · answer #2 · answered by mohrmann 3 · 0 0

fedest.com, questions and answers