Please Help:
Commercial vinegar was titrated with NaOH solution to determine the content of acetic acid, HC2H3O2. For 20.0 milimeters of the vinegar 26.7 milimeters of the 0.600-molar NaOH solution was required. What was the concentration of the acetic acid in the vinegar if no other acid was present?
2006-12-10 02:28:34 · 3 answers · asked by slickestboy2 1 in Science & Mathematics ➔ Chemistry
I'm pretty sure you weren't asking for a description of acetic acid, so...
The number of moles of acid and number of moles of base must be the same. As acetic acid is monoprotic, it will be a 1:1 reaction. Thus:
M(acid)V(acid) = M(base)V(base)
M(acid) = 26.7 * 0.600 / 20.0 = 0.801 M
2006-12-10 04:07:38 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
The hydrogen (H) atom in the carboxyl group (−COOH) in carboxylic acids such as acetic acid can be given off as an H+ ion (proton), giving them their acidic character. Acetic acid is a weak, effectively monoprotic acid in aqueous solution, with a pKa value of 4.8. A 1.0 M solution (about the concentration of domestic vinegar) has a pH of 2.4, indicating that merely 0.4% of the acetic acid molecules are dissociated.
2006-12-10 02:31:34 · answer #2 · answered by mastaocanasta 2 · 1⤊ 2⤋
The GMW of hydogen is a million so as that signifies that there is 29 g of Cl interior the given quantity of HCl. you spot that 0.5 of the Cl is utilized in MnCl2 so, subsequently, 0.5 of the Cl is interior the gas Cl2. Your answer is d) 14.6g.
2016-11-25 02:24:07 · answer #3 · answered by ? 4 · 0⤊ 0⤋