for H2,
van der waals forces (temporary dipole-temporary dipole attractions)
for CCl,
Van der waals forces (permanent dipole-permanent dipole attraction) this is due to the difference in electronegativity between C and Cl.
2006-12-10 03:05:01
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answer #1
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answered by mr warlords 2
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one million. A. Hydrogen Bonding. Hydrogen bonding is the main effectual intermolecular rigidity interior of NH2CH3 as not basically does it hydrogen bond interior of it self yet additionally helps Nitrogen to have a lone pair with helps with London-Dispersion Forces. 2. C. the answer is supersaturated because of the fact inspite of the warmth utilized (the completed of existence dissolving produces warmth), the solute isn't totally dissolved. If the answer became into unsaturated it would have dissolved totally on touch. If it have been saturated it would have taken stirring and then it would have thoroughly dissolved. 3. London Dispersion Forces. additionally oftentimes used as Van der Waals, those forces enable non everlasting polar dipole interactions to adhere to different Hydrogen gasses (H2). Your welcome :)
2016-10-18 01:39:52
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answer #2
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answered by Anonymous
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To clarify, is the last one CCl or CCl4?..coz if its CCl4 (which i think is most likely), both are non polar molecules so like what the first one said, they would only have the weakest of the IMFs..London dispersion forces...to add, all IMF of attraction have been generally classified as van der Vaal's forces...London dispersion forces, dipole-dipole attractions and hydrogen bond:)
2006-12-10 04:01:30
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answer #3
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answered by jill_quitayen 2
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The weakest of all. They are sometimes called dispersion forces, and other people call them van der Waal's forces.
They are present between all molecules, but if there is a stronger force, they become negligible.
2006-12-10 02:16:59
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answer #4
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answered by Gervald F 7
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what type of intermolecular forces are present in H2?
2015-11-05 14:35:16
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answer #5
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answered by Dimitri 1
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