Solve quadratic equation w/ quadratic formula and get decimal answers.?

Question

4x^2 - 2x - 13 = 0

Answer 1

x = {-b +- sqrt(b^2 - 4ac)}/2a

b^2 - 4ac
= 4 - 4 x 4 x -13
= 4 + 208
= 212

Therefore,
x = {2 +- sqrt(212)}/8
= (2 +- 14.56)/8
= 2.07 or -1.57

Answer 2

4x² - 2x - 13 = 0

Quadratic Formula

x = - b ± √b² - 4ac / 2a

a = 4
b = - 2
c = - 13

- - - - - -

x = - (- 2) ± √(- 2)² - 4(4)(- 13) / 2 (4)

x = (2 ± √4 + 208) / 8

x = (2 ± √4 + 208) / 8

x = (2 ± √212) / 8

x =( 2 ± 14.56021978 ) / 8

- - - - - - - - - - - - -- - - -

Solving for +

x = (2 + 14.56021978) / 8

x = 16.56021978 / 8

x = 2.070027472

x = 2.07 rounded to two decimal places

- - - - - - -

Solving for -

x = (2 - 14.56021978) / 8

x = 12.56021978 / 8

X = 1.570027472

X = 1.57 rounded to two decimal places

- - - - - - -s-

Answer 3

4x² - 2x - 13 = 0

x = [2±(2²+4*4*13)^¹/2] / (2*4)
x = [2±(4+208)^¹/2] / 8
x = [2±2*53^¹/2] / 8
x = [1±53^¹/2] / 4

x' = -1.57 ... or ... x'' = 2.07

₢

Answer 4

use quadratic equation! elementary peasy. -b +/- sq. root of b squared - 4ac ALLLL over 2a.. a is 4. b is -17. c is -4. i understand i wrote it confusingly attempt looking it up. good success!

Answer 5

x = [-(-2) ± √((-2)² - 4(4)(-13))]/2(4)
= [2± √212]/8
= 2.07 or -1.57

Answer 6

you got to do your homework yourself. From just getting the solution, you don't learn anything.