a. x - y + 1 = 0
b. x + y - 5 = 0
c. 2x + 3y - 11 = 0
d. 3x + 2y - 13 = 0
e. none of these
2006-12-10 01:35:28 · 6 answers · asked by Doug 2 in Science & Mathematics ➔ Mathematics
equation c
2006-12-10 01:37:57 · answer #1 · answered by raj 7 · 0⤊ 0⤋
First find slope: (3-1)/(1-4) = -2/3
You can write an equation in slope intercept form: y = (-2/3)x +b. Plug in one of the points you know to find b. 1 = (-2/3)(4) + b
b = 11/3, so y = (-2/3)x + 11/3
Now, multiply the entire equation by 3 to make everything an integer. You will get 3y = -2x + 11 Rewrite as 2x + 3y - 11 = y, which is c.
2006-12-10 09:40:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
y = ax + b
=>
a = (3-1) / (1-4) = 2/-3 = -2/3
=>
y = -2x/3 + b
=>
3 = -2/3(1) + b => b = (9+2)/3 = 11/3
=>
y = -2x/3 + 11/3
3y = -2x + 11
3y + 2x - 11 = 0
Answer: letter (c)
₢
2006-12-10 12:13:12 · answer #3 · answered by Luiz S 7 · 0⤊ 0⤋
(y-3)/(x-1) = (3-1)/(1-4)
(y-3)/(x-1) = -â
3(y-3) = -2(x-1)
3y - 9 = -2x + 2
2x + 3y -11 =0
Answer: c
2006-12-10 13:50:50 · answer #4 · answered by Ranna Renni 2 · 0⤊ 0⤋
fastest way to find out:
just substitue x=1;y=3 and x=4;y=1 in the LHS of the equations...if you get lHS+RHS..that's the answer...
the answer is 'c' btw..
2006-12-10 09:49:22 · answer #5 · answered by Anonymous · 0⤊ 0⤋
just plug in the two coordinate points, the equation that works for both is the answer which is c
2006-12-10 09:41:06 · answer #6 · answered by Eric M 2 · 0⤊ 0⤋