What's 2 plus 5 times 67 divided by 3 plus 45 minus 23????
2006-12-10 00:47:31 · 9 answers · asked by Teeeheee 2 in Science & Mathematics ➔ Mathematics
178.33
2006-12-10 00:53:33 · answer #1 · answered by cat m 4 · 0⤊ 0⤋
2 plus 5 times 67 divided by 3 plus 45 minus 23
=2+5*67/3+45-23
=2+(5*67/3)+45-23
=2+45-23+(5*67/3)
=24+(335/3)
=(72/3)+(335/3)
=407/3
=135(2/3)
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2006-12-10 00:58:08 · answer #2 · answered by San 2 · 0⤊ 0⤋
Order of Operations will help.
2+[(5 x 67)/3]+45-23
135 and 2/3 OR
135.666666666666666666666666666...
2006-12-10 00:57:36 · answer #3 · answered by Robbie F 2 · 0⤊ 0⤋
2 + (5* 67)/3 + 45 - 23 =
2 + 111 2/3 + 22 = 135 and 2/3
2006-12-10 00:50:57 · answer #4 · answered by Chris C 3 · 0⤊ 0⤋
If we follow the mathematical operators precedence rules then:
2+(5*67/3)+45-23=135.67
If we solve it sequentially in the order you said it, then:
2+5*67/3+45-23=178.33
2006-12-10 00:58:56 · answer #5 · answered by Noor O 2 · 0⤊ 0⤋
If there are no parenthesis or exponents in the problem, you're supposed to do multiplication and division first. So, 2+(5*67/3)+45-23=135.667
2006-12-10 00:59:40 · answer #6 · answered by crazydave 7 · 0⤊ 0⤋
135 2/3
2006-12-10 01:36:18 · answer #7 · answered by Mr. E 3 · 0⤊ 0⤋
2+(335/3)+22
2+162 1/3+22
186 1/3
2006-12-10 00:50:25 · answer #8 · answered by raj 7 · 0⤊ 0⤋
134.33333r
2006-12-10 00:57:17 · answer #9 · answered by grumpyoldman 4 · 0⤊ 0⤋