Can someone show me how? Heres the problem using absolute value. Thanks
3(2- l 6-8 l +5/4-5*2)+ squared 9+16
2006-12-09 22:48:57 · 7 answers · asked by bobbysgirlmeri 2 in Science & Mathematics ➔ Mathematics
This isn't algebra; it's just arithmetic.
2006-12-09 23:20:30 · answer #1 · answered by wwwwwwwfe 1 · 0⤊ 0⤋
that's PEMDAS. Solve first the number in the
Parenthesis,
Exponent
Multiplication or Division (whatever comes first)
Addition or Subtraction (whatever comes first)
that's a pre-algebra topic isn't it?
3(2- l -2 l +5/4-5*2)+ 81+16 (i considered squared 9 as 81)
3(2-(2) +5/4-10)+ 81+16
3(2- (2) +1.25 - 10)+ 81+16
3(0 + 1.25 - 10 ) + 81 + 16
3 ( 8.75 ) + 81 + 16
26.25 + 81 + 16
= 123.25
or 123 and 1/4 that's equal to 493 / 4..
just follow the rule in PEMDAS but others called it BEDMAS and B as Brackets
2006-12-10 07:59:18 · answer #2 · answered by racz_jay25 2 · 0⤊ 0⤋
if you subtract 6-8, you get -2, right? but since it is enclosed with the absolute value sign, the answer should still be +2...
then you solve 5*2...
3(2-(+2)+5/4-10))+(9+16)^2
you should remember to add/subtract from left to right inside the first parenthesis...
3(-35/4)+(9+16)^2
(-105/4)+(25)^2
(-105/4)+625
from here you can solve this i hope.
2006-12-10 07:09:55 · answer #3 · answered by nozmiat 3 · 0⤊ 0⤋
3(2- I 6-8 I +5/4-5*2)+squared 9+16=3(2-2+5/4-10)+81+16
= 3(5/4-10)+97
=3* -8.75 +97
= -26.25+97
=70.75 Ans.
2006-12-10 08:28:56 · answer #4 · answered by ATS 2 · 0⤊ 0⤋
3(2-(2)+5/4*2)+81+16
=3(0+5/2)+97
=15/2+ 97
=104+1/2
=209/2
2006-12-10 06:55:41 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
3(2-2+5/4-10)+81+16
=3(-35/4)+324/4+64/4
=-105/4+388/4
=283/4
=70 3/4
2006-12-10 07:10:44 · answer #6 · answered by raj 7 · 0⤊ 0⤋
3(2-2+5/4-5*2)+25*25
3(2-2+5/4-10)+625
3(2-3/4-10)+625
3(5/4-10)+625
3(-35/4)+625
-105/4+625
-105+2500/4
2495/4
I hope ive got ur symbols right(im not so gud at them)
2006-12-10 06:59:16 · answer #7 · answered by Anonymous · 0⤊ 0⤋