2006-12-09 22:46:40 · 6 answers · asked by VAIBHAVI 1 in Science & Mathematics ➔ Mathematics
[(5/3x-11x+9) = 0] x 3
5x-33x+27 =0
(-28x +27) -27 =0 - 27
-28x=-27
-28x/-28=-27/-28
x= 27/28
2006-12-09 23:02:02 · answer #1 · answered by bugr_bcr 2 · 0⤊ 0⤋
transpose 9 on the right side of the equation;
5/3x - 11x = -9
then 5/3x and 11x can be combined since they have the same variable, that is x. To get rid of the denominator 3, multiply the whole equation to 3;that would eliminate 3 in 5/3x while you multiply 3 on 11 and 9;
(5/3x - 11x = -9) *3
5x-33x = -27
-28x = -27
divide both sides by -28, to get x;
x = (-27/-28)
the answer is x = 27/28
2006-12-10 07:00:12 · answer #2 · answered by nozmiat 3 · 0⤊ 0⤋
5/3x - 11x+9=(5/3 - 11)x +9
= - 9.333 x + 9 Ans
2006-12-10 08:36:28 · answer #3 · answered by ATS 2 · 0⤊ 0⤋
5/3x - 11x + 9= 0
5/3x - 11x= -9
11x - 5/3x=9
(33/3 - 5/3)x=9
28/3x=9
x=9 * 3/28
x=27/28
PS: 33/3 it’s 11
2006-12-10 08:15:37 · answer #4 · answered by Juliya B 1 · 0⤊ 0⤋
5/3x-11x+9
x(5/3-11)+9
-9 1/3x+9
2006-12-10 15:05:25 · answer #5 · answered by ♥KiYa♥ 3 · 0⤊ 0⤋
(5/3 - 11)x +9
=(-28/3)x+9
if there were =0 on the right side then
28/3 x=9
x=9*3/28
=27/28
2006-12-10 06:57:49 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋