A BE condensate is an assembly of integer spin particles that are all in the ground state (the lowest energy state). It is so called because integer spin particles obey Bose Einstein statistics. The best known examples are the paired electrons in a superconductor (Cooper pairs) and the superfluid phase of Helium 4.
Quantum entanglement has no impact at all on E = mc^2. It also does not violate the limit of the speed of light, because information on the quantum state of one entangled particle cannot be transmitted to the other faster than the speed of light.
2006-12-09 20:52:49
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
Quantum Entanglement
A Bose-Einstein condensate is an unusual state of matter that arises because of quantum mechanical effects on a collection of entities called bosons.
Everything is either a boson or a fermion. The spin of an object determines whether it is a boson or a fermion. Elementary particles such as electrons, quarks, neutrinos, protons and neutrons are fermions. Photons4 are examples of bosons. Elementary particles have an intrinsic spin or turning motion, which must be a multiple of 1/2 due to quantum mechanics. Bosons are particles with integer spin such as 0, 1, 2, and so on. Fermions are particles with half-integer spin such as 1/2, 3/2, 5/2, and so on
In quantum mechanics, the position of an object is uncertain. An object has a definite probability of being at any given point in space. This probability is encoded in what-is-called a wave function. It is like a "cloud" that tells you the probability that an object has a certain location. If one concentrates a large number of identical bosons in a small region, then it is possible for their wave functions to overlap so much that the bosons loose their identity.
A collection of bosons can do this same thing. When this happens, a Bose-Einstein condensate forms
As regards the quantum entanglement violating E=MC square scientists differ. They feel that as per the information availalable at Eienstein's time perhaps it was held that it does not violate the equation but with more information now available ,while it cannot be claimed with any degree of cetainty that it is not violate but that it could if not it does. E's equation requires reformulation.
Does quantum entanglement violate the E= MCsquare.
The latter part of the answered has been reframed by me after studying the differing opinion of many . I have endeavoured to put it in as succinctly as possible.
2006-12-10 05:33:20
·
answer #2
·
answered by Prabhakar G 6
·
0⤊
0⤋