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Problem 1:

Prove that (2n)! < ((2n+1)/2)^2n

Problem 2:

if x^2 - ax + b=0 and x^2 - bx +a=0 both have real distinct roots for real a,b then prove that the solution set (a,b) is (5,6)


Ppl although any kind of solution is welcome please try to come up with a clever one as my own version of solutions are rather round about!

Thank you!

2006-12-09 17:46:25 · 6 answers · asked by Rajaram N 2 in Science & Mathematics Mathematics

6 answers

i had a similar questions..check out http://www.schoolpiggyback.com ...thye have other students that help ya out..maybe someone from your class : ) goodluck ...

2006-12-09 17:49:10 · answer #1 · answered by Anonymous · 0 0

Your attitude and good judgment are completely ok different than for the final step. The make the main of merchandising one apple is unquestionably 21/one hundred ten as you have calculated. yet for looking the % benefit , you're able to desire to precise 21/one hundred ten as share to the fee of one apple i.e. 10/11. subsequently, the proportion income is a hundred*(21/one hundred ten)/(10/11) that's 21%.

2016-12-30 05:15:36 · answer #2 · answered by Anonymous · 0 0

I have my doubts about your solutions. If you'd post a little info to convince me that you'd actually done something then I'd help. It appears that you want someone else to do your work.

2006-12-09 18:04:15 · answer #3 · answered by modulo_function 7 · 1 0

Those are very elemantary, you must be kind of slow?

2006-12-09 17:49:11 · answer #4 · answered by DOOM SQUIRREL!! 1 · 0 2

ask aryabhatta

2006-12-09 18:19:23 · answer #5 · answered by siddharth s 2 · 0 0

cheater!

2006-12-09 17:48:25 · answer #6 · answered by cathandra 2 · 1 1

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