Mismas, one of Saturn's moons, has an orbital radius of 1.87 * 10^8 meters and an orbital period of about 23.0 hours. Use Newton's version of Kepler's third law to find Saturn's mass.
Please help me with this problem.
I'm having trouble understanding it.
I asked this once before, but I was confused with the answers and the formula's used.
2006-12-09 14:38:24 · 2 answers · asked by vicky p 1 in Science & Mathematics ➔ Physics
Don't post your homework questions here. They were given to you for you to solve, not for us to solve.
If you don't understand it speak to the person who gave you the homework for help or just read whatever material your class uses (any notes you've taken or were given, textbook, etc).
2006-12-09 14:55:16 · answer #1 · answered by bestonnet_00 7 · 0⤊ 2⤋
Use 4(?²)r³ = G(M)(p²) the situation r is the Moon's orbital radius 3.80 4 x 10^8 meters, p it era in seconds (2,358,720 seconds) and G = 6.sixty seven x 10^-11 Nm^2/kg^2 M = 4(?²)r³/(G(p²)) M = a million.86 x 10^24 kilograms
2016-12-30 05:08:36 · answer #2 · answered by boynton 3 · 0⤊ 0⤋