The asteroid Ceres has a mass of 7.0 * 10^20 kg and a radius of 500 km.
a. What is the gravity on the surface of Ceres?
b. How much would a 90-kg astronaut weigh on Ceres?
Please help me with this problem.
I'm having trouble understanding it.
2006-12-09 13:39:54 · 3 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Physics
a)Fg=(Gm1m2)/r^2
Fg=(6.67e-11 x 7.0e20 x m2)/500000^2
note 500 km should be changed to 500000m
m2 is the mass of the smaller object, but gravity is always constant, so it can be cancel out. see below.
Fg=mg
therefore
m2g=(6.67e-11 x 7.0e20 x m2)/500000^2
cancel out m2
g=6.67e-11 x 7.0e20/500000^2
g=0.19
b)Fg=mg
Fg=90 x 0.19
Fg=16.8N
2006-12-09 13:57:23 · answer #1 · answered by 3.141592653589793238462643383279 3 · 0⤊ 0⤋
only use the easy gravitation equation and plug interior the right values, previously calculation F = G x M1 x M2 /d ^2 G = 6.sixty seven x 10^-11 N-m^2 / kg^2 M = 8.56 &activities; 10^20 kg. M = sixty 3.a million kg d = 1140 km = 1140000 m
2016-11-30 09:17:51 · answer #2 · answered by ? 4 · 0⤊ 0⤋
the Surface gravity is 0.27 m/s²
as for the second part go to this website scroll down to chapter 14 problem 1 and just substitute the 90kg for the 100 kg and u should get ur answer. hope this helps.
http://ceres.hsc.edu/homepages/classes/astronomy/fall97/problems/probs9.html
2006-12-09 13:59:23 · answer #3 · answered by Fatima 1 · 0⤊ 0⤋