If person A is traveling at 80% the speed of light in a vehicle with a perfect timekeeping mirror, that bounces light off the mirrors to record time very accurately, and person B was on the outside watching at the vehicle pass by, what would the time difference between the persons be to the exact decimal?
2006-12-09 11:35:48 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
i dont know and i dont care
2006-12-09 11:38:55 · answer #1 · answered by stardust 3 · 0⤊ 1⤋
Both observers will view the others clock as running slower than their own.
At 80% of the speed of light the time dilation is obtained from the Lorentz Factor (LF), or:
LF = 1/sq rt(1-[v^2/c^2])
LF = 1/sq rt(1-[.8*186e3^2/186e3^2])
LF = 1.67 (the exact decimal is 1.6666......a repeating decimal)
In order to measure the observer's time as just one minute, it will take the other observer 1 minute and 40.2 seconds.
Note: Speed of light approximated to 186,282,397 MPS.
2006-12-09 13:03:23 · answer #2 · answered by LeAnne 7 · 0⤊ 0⤋
Hi. This site has the formula for time dilation, but the exact decimal? There would have to be something special (no pun) about 80%. : http://en.wikipedia.org/wiki/Time_dilation
2006-12-09 11:41:34 · answer #3 · answered by Cirric 7 · 0⤊ 0⤋
80% the speed of light
2006-12-09 12:45:33 · answer #4 · answered by Joel M 1 · 0⤊ 0⤋
1.666593 hours
2006-12-09 12:46:07 · answer #5 · answered by Chug-a-Lug 7 · 0⤊ 0⤋