English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Why does a car need higher torque to run over a higher inclination...

Why we need higher gear..

Energy: Torque*angular velocity
When we vary the torque using gears the speeed decreases and theoretically..the energy remains the same...

Now if we are providing the same energy why we cannot do the same thing with it?

2006-12-09 07:55:21 · 5 answers · asked by robin 3 in Science & Mathematics Physics

5 answers

Wehn your car is in a higher gear, the resistance to movement is higher. Assume the car is outputting the torque T at a given rpm W. the angular velocity of the tires in say 1st gear (a lower gear) is less than the angular velocity of the tires in say 4th gear ( a higher gear). The frictional coefficient between the tires and the ground is still the same no matter what gear you are in. This helps to detrmine the opposing torque the tires exert on your drivetrain. Let the angular velocity of the tires in 1st gear be w1and in fourth gear be w4. Let the mass of the car be m. Let the angular acceleration of the car in first gear be a1 and in fourth be a4. Notice that w1 and w4 depend on W. W depends on the torque the engine can apply T as a function of rpm. rpm is the engine speed and depends on what gear you are in and what speed you are going. Man I think I need to think on this one a little further. I almost have a Green's Fuction thing going on here.

BTW, morrow you aren't taking into accouint that there are no lever arms that are changing here. Only the rotatonal velocities of the tires hence the rotational speeds of the driven gears are changing. I am sure that someone in Detroit has a good answer for this but I don't think I have the attention span for it right now.

2006-12-09 08:16:04 · answer #1 · answered by Anonymous · 0 0

Torque is a rotational force, T=Force*distance, in order to go up a hill sometimes you gear down increasing the gears diameter, since the force always remains constant (from the crank shaft) the torque increases and the angular velocity drops.

Also think of torque as the force required to overcome resistive forces (like engine friction and heat) to keep moving at a constant velocity.

2006-12-09 08:09:26 · answer #2 · answered by Anonymous · 0 0

onlyafewill... replied this so properly, yet I only opt for to operate my 2 inch pounds... Torque in elementary words exists even as there is resistance. stress can not be utilized if there's no opposing stress. suited torque calculations assume that the opposing/resisting stress equals (or exceeds) the stress utilized. ;-D there is an automobile device comparable to a wrench that has a scale close to at least one end, hostile to which a pointer will element out the stress utilized. This scale is measuring torque. Bolts typically opt for a particular quantity of torque utilized to carry the parts mutually without warping or braking some thing. ignore about perfect torquing at your human being fee!

2016-11-30 09:02:14 · answer #3 · answered by ? 4 · 0 0

In your example, a car, you are limited by your power source; the car's engine. For an infinitely strong engine, you are correct, energy is energy. However, engine limitation only allow it to put out so much torque at certain rpm's.

As you move around an engine's rpm range, you will get different torque capabilities. You can change these torque capabilities through gearing.

m

2006-12-09 08:59:00 · answer #4 · answered by Mukluk 2 · 0 0

On a very simple level, go over to the nearest door. Go to the side where the door opens away from you, and close it open. Now, push it open as you normal would where the handle is, and notice how easy that is. Now, try sliding your hand towards the hinges, and as you do, you'll notice it requires a lot more effort to keep the door open. That's what torque is!

2006-12-09 07:59:09 · answer #5 · answered by Where the 'morrow lives 2 · 0 0

fedest.com, questions and answers