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Two, actually. Should I put them together in one box (they'll prolly get tangled, though) or in separate boxes and then put them in a nice bag?

Any other ideas will be appreciated too. Thanks in advance.

2006-12-09 05:01:39 · 7 answers · asked by Aimers 3 in Beauty & Style Fashion & Accessories

I like the "separate boxes-stacked on top of each other-add a ribbon" idea.

Thanks everyone!

2006-12-09 08:52:11 · update #1

7 answers

You can go to a jewelry store or in a department store and ask for a jewelry gift box... They have all types of gift boxes, for necklaces, rings, and bracelets, etc... I think it would be cute if you got one necklace box and another bracelet box and wrapped your necklaces in those separately and then placed them on top of each other and tied them together with a pretty bow.... Wrapping presents is fun, just be creative with it, good luck!!

2006-12-09 05:12:37 · answer #1 · answered by KC 3 · 1 0

You should put them in different boxes, wrap the boxes, and then put them in a bag (separately). I guess it makes Christmas more fun because you are opening more gifts.

2006-12-09 13:07:10 · answer #2 · answered by confused 2 · 1 0

put each in a small box then put the boxes on top of each other and tie them with a ribbon and put a bow on top..that would look nice

2006-12-09 13:17:41 · answer #3 · answered by Aberollisterxo 3 · 0 0

I would put them in two boxes and then put them in the same bag. If your put them in the same box, they might get tangled.

2006-12-09 13:09:54 · answer #4 · answered by Samantha 2 · 0 0

It's better if you buy those gift card boxes in the dollar store, they tend to be more cuter and cheaper and just put your necklaces there.

2006-12-09 13:04:06 · answer #5 · answered by merabluette 2 · 1 0

I believe in seperate boxes and in nice bags would be an excellent idea..

2006-12-09 13:10:13 · answer #6 · answered by Anonymous · 0 0

wrap them separately.........I think would be fine. Best of luck to you.

2006-12-09 13:20:23 · answer #7 · answered by cajunrescuemedic 6 · 0 0

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