Does the rotation of Earth affect gravity?

Question

I mean to create artificial gravity in space you need a very large object about a mile in diameter that has to rotate. So I'm saying if Earth span faster would that create a stronger Gravitational pull.

Answer 1

NO. You're talking about centrifugal force. That wouldn't work on the earth, it only works when the floor you stand on is spinning. Increasing the spin of the earth would only throw us off.

Answer 2

YES
Obviously, the rotation of earth affects gravity because it's been known for a long time that the gravity at the equator is measurably less than at the poles. Don't try to separate centripetal acceleration from gravitational acceleration, folks, or you'll have to answer to A. Einstein, who proved they are indistiguishable.

You don't need a huge rotating object to recreate gravity in space. 100 m diameter is plenty adequate. At this size a gravitational field of 1g at the outer rim would require only 1.9 rev/min

A faster spinning earth would create LESS gravity everywhere except the poles.

Answer 3

Why the heck are people talking about jupiter?? leave the gods out of this, by toutatis!!
the rotation of earth creates a very small throwing-out effect. It's the reason why people standing on the equator weigh slightly lighter than those standing at the poles, provided you keep the same distance from earth's center.
This is why the earth, and all other planets/stars for that matter, are flattened at their poles and bulging at their respective equators.

what you're talking about, and object that's HOLLOW from the inside, right? yes, if you spin it well enough, you can replicate gravitational pull. force is force whether it's by gravity or centrifugal. in fact, this rotating-hollow-cylinder concept has been illustrated on many tv programs that were talking about the new Int'l Space Station, or setting up a big one in orbit. If a part of the station is kept spinning, then the astronauts can go there to work out, and to acclimatize themselves to gravity before returning to earth.

in terms of formulae, the centrifugal force you'd make in your object would be F = m*v^2 / r Or F = m * w^2 * r
v is linear velocity at the tip, w is angular velocity (easier to calculate)

and then you gotta equate it with local gravity,
F = m * g

so, you need g = w^2 * r
you r is half a mile (radius). get g in appropriate units.
then you'll get w (referred to as omega)
this w will be in radians per sec.

Answer 4

The rotation does not impression gravity consistent with se, whether it does reason an incredibly minor obvious centrifugal rigidity that acts in opposition to gravity, hence lowering its effects slightly. If the rotational speed have been to alter suddenly, the vertical effects may well be trivial while in comparison with the horizontal effects, which might basically be an earthquake with a Richter magnitude of one hundred or greater!

Answer 5

No, the gravity at the surface of the earth has only to do with the mass and radius of the earth. Jupiter has a higher gravitational pull because it's many times more massive than the earth.

Answer 6

when the earth rotate faster,angular velocity of the earth increses.when the planet rotates,a mass are able to stay on the planet's surface because the centripedal force is equivalent to the gravitational force.The planet and the mass moves with same angular velocity.when angular velocity increases,the centripedal force increses.therefore gravitaional pull which are defined as gravitational force per unit mass increases.therefore a stronger gravitational pull is produced.

Answer 7

Consider an object of mas m on the surface of the Earth.
We have the equation as per Newton's law of universal gravitation.
mg=G*M*m/R^2
g=G*M/R^2
g=acceleration due to gravity m/sec^2
G=universal constant N m^2 kg^-2
R=radius of Earth m
Thus rotation of Earth has no bearing apparently. However rotation of Earth does creates centrifugal acceleration which subtracts from this figure. The rotational velocity at equator is 465.11m/sec. Centrifugal acceleration =v^2/R=5.3687*10^-9 m/sec^2.As can be seen it is negligible. Please note this acceleration subtracts from that due to gravity and not add to it. So earth rotated 100 times faster on its axis it will reduce the acceleration due to gravity considerably and not add to it.

Answer 8

Well in this case probably because jupiter has a greater rotation than earth and it has and immense gravitational pull, but another thing is because of its size that it can spin fasster than the earth and
be able to support such a gravitational pull without crushing itself.

Answer 9

NO!! You are confusing gravity (a product of masses) and centrifugal force(a product of rotational velocity)!

Answer 10

no, u r rong dear...
u r talking about the centrifugal force....
earth's gravity is only effected by Height...and depth