f(x)=10^(x/2) g(x)=log (x^2)
2006-12-09 04:46:54 · 4 answers · asked by jessica h 1 in Science & Mathematics ➔ Mathematics
1)
f(x)=10^(x/2)
y =10^(x/2)
=>
x =10^(y/2)
log x = log 10^(y/2)
log x = (y/2)log 10
log x = y/2
y = 2*log x
y = log x²
___________________________________________
2)
g(x) = log (x^2)
y = log (x^2)
=>
x = log (y²)
x = 2*log y
x/2 = log y
y = 10^(x/2)
₢
2006-12-09 05:31:37 · answer #1 · answered by Luiz S 7 · 0⤊ 0⤋
f(x)=10^(x/2) the inverse is f(x) = 10‾x/2
g(x)=log(x^2) the inverse is g(x) = (1)/log(x^2)
2006-12-09 13:15:28 · answer #2 · answered by SHIBZ 2 · 0⤊ 0⤋
inverse of f(x) is log(x/2) and g(x)=10^(x^2)
2006-12-09 13:04:06 · answer #3 · answered by lynn 2 · 0⤊ 0⤋
You should do the opposite of asking questions like this.
2006-12-09 12:50:15 · answer #4 · answered by somewherein72 4 · 0⤊ 0⤋