2006-12-09 03:50:07 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(1) equation X+2Y=-17
(2) equation 2x +1y=-16
(1).2 = 2X+4Y=-34
(1)-(2)= 3Y=-18
Y=-6
PUT Y IN HIS VALEUR IN THE FIRST EQUATION OR THE SECONDE
(1) = X +(2)(-6)= -17
X-12=-17
X = -17 + 12
X = -5
2006-12-09 04:03:59 · answer #1 · answered by ****MIRO**** 2 · 0⤊ 0⤋
x+2y= -17
x= -17-2y
so 2x+y= -16
Now putting the value of x= -17-2y in the above equation
2(-17-2y)+y= -16
-34-4y+y= -16
-3y= -16+34
-3y=18
y= -18/3= -6
now x= -17-2y= -17-2(-6)= -17+12= -5
so x= -5, y= -6 (solved)
2006-12-09 04:03:46 · answer #2 · answered by aminnyus 2 · 0⤊ 0⤋
x + 2y = -17 .........(1)
=> x = -17 -2y ..........(2)
2x + 1y = -16 ...........(3)
sub (2) in (3),
2 ( -17 - 2y) + y = -16
=> -34 -4y + y = -16
=> 3y = -18
=> y = -6 ........(4)
sub (4) in (2),
x = -5
2006-12-09 03:58:46 · answer #3 · answered by vinoth k 1 · 0⤊ 0⤋
2x + 1y = -16
x + 2y = -17
2x + 1y = -16
-2x-4y= 34
-3y=18
y= -6
2x-6= -16
2x= -10
x= -5
2006-12-09 03:58:06 · answer #4 · answered by 7 · 0⤊ 0⤋
the second expression y= -16 -2x
x -4x -32 =-17 ---> -3x = -17+32 = -15
x=5 y = -6
2006-12-09 04:18:23 · answer #5 · answered by maussy 7 · 0⤊ 0⤋
x+2y=-17
4x+2y=-32[rom second eqn.*2]
subtracting
-3x=15
x=-5
-5+2y=-17
y=-6
verifty[subs.values in eqn.2]
-10-6=-16
ok
2006-12-09 04:49:19 · answer #6 · answered by openpsychy 6 · 0⤊ 0⤋
DO YOUR OWN HOMEWORK.
2006-12-09 03:53:07 · answer #7 · answered by kittenpie 3 · 0⤊ 0⤋